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Example problem on sum-of-the-years-digits method of depreciation

Example problem on sum-of-the-years-digits method of depreciation -1


A company has purchased an equipment whose first cost is Rs. 1,00,000 with an estimated life of eight years. The estimated salvage value of the equipment at the end of its lifetime is Rs. 20,000. Determine the depreciation charge and book value at the end of various years using the sum-of-the-years-digits method of depreciation.

Given data
Purchase price, P = . 1,00,000
Salvage value, F = . 20,000
Life of an asset, n = 8 years

Formula used
Dt = Rate*(P – F)
Bt = Bt–1 – Dt

Solution
Sum of years = n(n + 1)]/2 = 8(8+1)/2 = 36
Rate of years
            First year = 1/36
            Second year = 2/36
            Third year = 3/36
            Fourth year = 4/36
            Fifth year = 5/36
            Sixth year = 6/36
            Seventh year = 7/36
            Eighth year = 8/36

End of Year
Depreciation (Dt = Rate*(P – F)
in
Book Value (Bt   = Bt–1  – Dt)
in
0

1,00,000
1
17,777.77
82,222.23
2
15,555.55
66,666.68
3
13,333.33
53,333.35
4
11,111.11
42,222.24
5
8,888.88
33,333.36
6
6,666.66
26,666.70
7
4,444.44
22,222.26
8
2,222.22
20,000.04




Example problem on sum-of-the-years-digits method of depreciation -2


A company has purchased an equipment whose first cost is Rs. 1,00,000 with an estimated life of eight years. The estimated salvage value of the equipment at the end of its lifetime is Rs. 20,000. Determine the depreciation charge and book value at the end of 5th year using the sum-of-the-years-digits method of depreciation.

Given data
Purchase price, P = . 1,00,000
Salvage value, F = . 20,000
Life of an asset, n = 8 years
t = 5

Formula used
Dt = {[n − t + 1]/[n(n + 1)]/2} * (P – F)
Bt = {[(P – F)] [(n – t)/n] [(n − t + 1)/(n + 1)]} + F

Solution
D5       = {[n − t + 1]/[n(n + 1)]/2} * (P – F)
            = {[8 − 5 + 1]/[8(8 + 1)]/2} * (1,00,000 – 20,000)
D5       =. 8,888.88

B5        = {[(P – F)] [(n – t)/n] [(n − t + 1)/(n + 1)]} + F
            = {[(1,00,000 – 20,000)] [(8 – 5)/8] [(8 − 5 + 1)/(8 + 1)]} + 20,000
            = 80,000 * (3/8) * (4/9) + 20,000
B5        =. 33,333.33

Result
At the end of 5th year,
Depreciation charge = . 8,888.88
          Book value = . 33,333.33